SSC CHSL Model Paper 20

Question : 74 of 100

Marks: +1, -0

What is the total surface area of a one-side open cubical box of outer side of length 5 cm. and thickness 0.5 cm?

Solution:

The total surface area of a cube = surface area of the sides - surface area of the open side

= (6 × 5 ^2 - 5 ^2) + (6 ×4 ^2 - 4 ^2)

= 125 + 80

= 2 05 \cm ^2 .

Go to Question:

Prev Question

Next Question