SSC JE Mechanical Engineering 2018 Set 1 Paper

Question : 125 of 200

Marks: +1, -0

What will be the change in length (mm) of a steel bar having a square cross section of dimension 40 mm × 40 mm, which is subjected to an axial compressive load of 250 kN. If the length of the bar is 4 m and modulus of elasticity is E = 250 GPa?

2.5
1.25
2
1.5

Validate

Solution:

Given:

A = 40 × 40 \mm^2, P = 250 KN, l = 4 m, E = 2506 Pa

δl={Pl}/{AE}={250×10^3×4×10^3}/{40×40×250×10^3

10/4=2.5

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