SSC MTS 2 Aug 2019 Shift 1 Paper

Tips & Tricks
Given:
a : b = 3 : 4; b : c = 4 : 5; c : d = 5 : 6
Calculation:
On equating, a : b : c : d = 3 : 4 : 5 : 6
⇒ required fraction = ${\left(\frac{\mathrm{a}}{\mathrm{d}}\right)}^{10}$
= ${\left(\frac{3}{6}\right)}^{10}={\left(\frac{1}{2}\right)}^{10}$
= 1/1024
Required sum of numerator & denominator = 1 + 1024 = 1025