SSC MTS 2 Aug 2019 Shift 1 Paper

Calculation:
Time taken by first man to cover journey = 2 PM – 6 AM = 8 hours
Time taken by another man to cover journey = 3 PM – 8 AM = 7 hours
Let total distance from P to Q be 56x km (LCM of 8 & 7)
⇒ Speed of first man = 7x km/hr
⇒ Speed of second man = 8x km/hr
⇒ Distance covered by first man in 2 hours = 14x km
⇒ Remaining distance = 56x – 14x = 42x km
⇒ Time taken to meet each other = 42x/ (7x + 8x) = 42/15 hrs
= 2 hrs 48 min
⇒ Time of meeting = 8:00 + 2:48 = 10:48 AM