SSE JE Electrical Engineering 10 Dec 2020 Papers

Current carried by bulb(I) = 0.5 A
For t = 1 second
Q = I × t = 0.5 C
1 electron has a charge of $1.6\times {10}^{-19}\mathrm{C}$
For 0.5 C number of electrons passing through a cross-section of the filament is given as $=\frac{0.5}{1.6\times {10}^{-19}}$ $=3.125\times {10}^{18}$ electrons/s