∫ \sin^{-1}\sqrt{x/{a+x} dx =

Correct Answer is : tan−1(√xa)(a+x)−√ax+c

cosec (\sqrt{x/{a+x})(x/a) + ax + c

\cos^{-1}(\sqrt{x/a})(a-x)^2 - \sqrt{ax} +c

\cos^{-1}(\sqrt{x/a})(a+x) - \sqrt{ax} +c

\tan^{-1}(\sqrt{x/a})(a+x) - \sqrt{ax} +c

TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

∫ sin−1√

a+x

dx =

Go to Question:

Prev Question

Next Question