TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 72 of 160

Marks: +1, -0

∫

x2−1

x3√2x4−2x2+1

dx =

√2x2+2+
3
x2
+c
√2x2−
1
x2
+2+c
√2x2+x−2+c
1
2
√2−
2
x2
+
1
x4
+c

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