TS ICET 2017 Question Paper with Solutions for online practice

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Question : 122 of 200

Marks: +1, -0

If x + y = z. then

x^3 + y^3

+ 3xyz =

0
1
$z^3$
- $z^3$

Solution:

Given :

x+y=z

⇒x+y+(–z)=0

∴x^3+y^3+(–z)^3=3xy(–z)

⇒x^3+y^3–z^3=–3xyz

⇒x^3+y^3+3xyz=z^3

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