TS ICET 23 May 2019 Shift 2 Paper

Question : 118 of 200

Marks: +1, -0

cos (A + 45° + sin (A - 45°)

Solution:

\cos (A+45^{∘})+\sin (A-45^{∘})

=\cos A \cos 45^{∘}-\sin A \sin 45^{∘}+\sin A \cos 45^{∘}

-\cos A \sin 45^{∘}

=0( ∵ \sin 45^{∘}=\cos 45^{∘}=\;{1}/{√{2}})

Go to Question:

Prev Question

Next Question