TS ICET 23 May 2019 Shift 2 Paper

Question : 119 of 200

Marks: +1, -0

cos^2

A = sin A tan A ⇒

cot^6 A- cot^2 A

Solution:

Given

\cos^2=\sinA.\tanA

⇒ \cos ^{2} A=\;{\sin ^{2} A}/{\cos A}

⇒ \cot ^{2} A=\sec A

\cot ^{6} A-\cot ^{2} A=\cot ^{2} A(\cot ^{4} A-1)

=\cot ^{2} A(\sec ^{2} A-1)

=\cot ^{2} A(\tan ^{2} A)

=1

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