TS ICET 23 May 2019 Shift 1 Paper

Question : 125 of 200

Marks: +1, -0

If x - 3 divides

x^4-2x^2+3x^2-mx+3

, then m =

Solution:

Since

x -3

is a factor of

x^{4}-2 x^{3}+3 x^{2}-m x+3=0

∴ 3^{4}-2(3)^{3}+3(3)^{2}-3 m+3=0

⇒ 3 m=81-54+27+3

m=\;{57}/{3}=19

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